find the total surface area of the box made by folding the net given below (takeπ=3.14) leave answer to one decimal place
Answers
Answer:
Solution
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Correct option is B)
Given: Side of the cube =40 cm and radius of the cylinder =20 cm and height of the cylinder =50 cm
Volume of cube =(side)
3
=(40)
3
=64000 cm
3
Volume of cylinder =πr
2
h
=3.14×(20)
2
×50
=62800 cm
3
So, total volume of solid =64000+62800=126800 cm
3
Now, surface area of cube =6(side)
2
=6(40)
2
=9600 cm
2
The surface area of cylinder =2πrh
=3.14×20×50
=6280 cm
2
∴ Total surface area of solid =9600+6280=15880 cm
2
Step-by-step explanation:
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