Find the total surface area of the cubouds of length , breadth and heigth as given below :
i) 12 cm, 10 cm, 5 cm
ii) 5 cm, 3.5 cm, 1.4 cm
iii) 8 m, 5 m, 3.5 m
iv) 2.5 cm, 2 m, 2.4 m
Answers
Answer:
(1) length =12 cm breadth =10 cm height =5 cm
TSA=2(lb+bh+lh)=2[12×10+10×5+5×12]
TSA=2[120+50+60]=2×230
[TSA=460cm²]
(2) length =5 cm breadth =3.5 cm height =1.4 cm
TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5]
TSA=2[17.5+4.90+7.0]=2[29.4]
[TSA=58.8cm²]
(3) length =2.5 cm breadth =2 m height =2.4 m
TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025]
TSA=2[0.05+4.8+0.0600]=2[4.91]
(4) length =8 m breadth =5 m height =3.5 m
TSA=2(lb+bh+lh)=2[8×5+5×3.5+3.5×8]
TSA=2[40+17.5+28.0]=2[85.5]
[TSA=171.0m²]
Answer:
(I) length =12 cm breadth =10 cm height =5 cm
TSA=2(lb+bh+lh)=2[12×10+10×5+5×12]
TSA=2[120+50+60]=2×230
TSA=460cm2
(II) length =5 cm breadth =3.5 cm height =1.4 cm
TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5]
TSA=2[17.5+4.90+7.0]=2[29.4]
TSA=58.8cm2
(III) length =8 m breadth =5 m height =3.5 m
TSA=2(lb+bh+lh)=2[8×5+5×3.5+3.5×8]
TSA=2[40+17.5+28.0]=2[85.5]
TSA=171.0m2
(IV) length =2.5 cm breadth =2 m height =2.4 m
TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025]
TSA=2[0.05+4.8+0.0600]
TSA=2[4.91]