Question

Find the total surface area of the cylinder whose radius 3.5cm
and height is 11.5cm​

Answer 1

Chapter 16: Surface Area And Volume Exercise – 16.2

Question: 1

Consider a tent cylindrical in shape and surmounted by a conical top having height 16 m and radius as common for all the surfaces constituting the whole portion of the tent which is equal to 24 m. Height of the cylindrical portion of the tent is 11 m. Find the area of Canvas required for the tent.

Solution:

The diameter of the cylinder given in the question is 24 m.

a tent cylindrical in shapeRadius (R) = 12/2 = 12 m

The height of the Cylindrical part (H1) given in the question is 11m

So, Height of the cone part (H2) = 5 m

Now,

Vertex of the cone above the ground = 11 + 5 = 16 m

Curved Surface area of the Cone (say, S1) = πRL = 22/7 × 6 × L

Where,

So,

Curved Surface Area of Cone (S1) = 22/7 × 12 × 13 .... E.1

Curved Surface Area of Cylinder (S2) = 2πRH1

S2 = 2π(12)(11) m2 .... E.2

To find the area of Canvas required for tent

S = S1 + S2 = E.1 + E.2

S = 22/7 × 12 × 13 + 2 × 22/7 × 12 × 11

S = 490 + 829.38

S = 1319.8 m2

S = 1320 m2

Hence, the total Canvas required for tent (s) = 1320 m2