Find the total surface area of the following cuboids.
a length = 7 cm, breadth = 4 cm, height = 3 cm
b length = 4 m, breadth = 2 m, height = 2 m
e length = 45 cm, breadth = 45 cm, height = 45 cm
d length = 8 m, breadth = 4 m, height = 2 m
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Answer:total surface area of cuboid =2(lb+bh+bl)
=2(7×4+3×4+21)=2(28+12+21)
=2(40+21)
=2(61)=122
TSA OF CUBOID = 2 ( lb+bh+lh )
For a. TSA = 2 ( 4×2 + 2×2 + 4×2 )
= 2 ( 8+4+8 )
= 2 × 20
= 40 m^2
For b. TSA = 2 ( 8×4 + 4×2 + 8×2 )
= 2 ( 32+8+16 )
= 2 × 56
= 112 m^2
Step-by-step explanation:
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