Find the total thrust acting on the bottom surface of a tank 4 m long, 2 m broad, & 2 m deep when fully filled with water. The density of water = 10^3 kg/m^3
Answers
Answer:
Pressure is equal to force times area, so 156,800 N/ 8 m2 is 19,600 Pa.
Explanation:
When a tank is completely filled with water, the weight of the water and the pressure it puts on the tank's bottom surface must be taken into account to determine the overall thrust operating on the surface.
The following method can be used to determine the water's weight:
Weight is equal to mass times gravity.
where Gravity = 9.8 m/s2 and Matter = Volume Density (acceleration due to gravity)
The tank's water content is measured as follows:
Capacity is calculated as follows: 4 m x 2 m x 2 m = 16 m3
Water has a mass of 10-3 kilogrammes per cubic metre. As a result, the water's bulk is:
16,000 kg is equal to 16 m3 times 10 3 kg/m3, or mass.
We can calculate the weight of the water using the weight formula:
16,000 kg x 9.8 m/s2 = 156,800 N is the weight formula for mass and gravity.
We must now take into account the pressure that the water exerts on the bottom surface of the vessel in order to calculate the overall force operating there. The expression for pressure is:
Power x Radius = Pressure
where Area is the size of the tank's bottom surface and Force is the water's weight in pounds.
The tank's lower surface size is as follows:
Area is equal to Length x Breadth (4 m x 2 m) = 8 m squre.
The pressure that the water exerts on the tank's bottom area can be calculated using the pressure formula:
Pressure is equal to force times area, so 156,800 N/ 8 m2 is 19,600 Pa.
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