Question

Find the tower's height(h-opposite side AB) from the given figure where BC is the adjacent side. Use the trigonometric ratio ‘Tan’.

Answer 1

I don’t know really


Pls make me as nrain lost pls

Answer 2

Hence, The Height Of The Tower Is 86.60 Km

GIVEN

Distance between the foot of the tower and point of observation = BC = 50m

Angel of elevation = θ = 60°

TO FIND

Height of the Tower.

SOLUTION

We can simply solve the above problem as follows -

From the figure, we can observe that ABC is a right-angled triangle

Applying the law of tangent in ΔABC

tanθ = Ratio of the opposite side of the triangle to the opposite side

$\tan(θ) = \frac{AB}{BC}$

$\tan(60) = \frac{AB}{50}$

$BC\tan(60) = AB$

We know that,

tan60 = √3

BC = 50

Putting the values in the above equation, we get

AB = 50√3 km

Putting √3 = 1.73

AB = 50 × 1.73 = 86.60km

Hence, The Height Of The Tower Is 86.60 Km

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