find the trigonometic ratios of 45°, in a right-angled
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Trigonometrical Ratios of 45°
Let a rotating line →OX rotates about O in the anti-clockwise sense and starting from the initial position →OX traces out ∠AOB = 45°.
Take a point P on →OY and draw \(\overline{PQ} ...
Now, ∠OPQ = 180° - ∠POQ - ∠PQO.
= 180° - 45° - 90°
= 45°.
Therefore, in the △OPQ we have, ∠QOP = ∠OPQ.
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