Math, asked by khansa2004, 8 months ago

find the Trigonometric function of -180​

Answers

Answered by carrymittini
2

Answer:

What will be the unit digit of the squares of the following numbers?

(i) 81(ii) 272(iii) 799(iv) 3853 (v) 1234(vi) 26387(vii) 52698(viii) 99880 (ix) 12796(x) 55555

Sol: (i) ∵ 1 × 1 = I

∴ The unit’s digit of (81)2 will be 1.

(ii) 2 × 2 = 4

The unit’s digits of (272)2 will be 4.

(iii) Since, 9 × 9 = 81

The unit’s digit of (799)2 will be 1.

(iv) Since, 3 × 3 = 9

The unit’s digit of (3853)2 will be 9.

(v) Since, 4 × 4 = 16

The unit’s digit of (1234)2 will be 6.

(vi) Since 7 × 7 = 49

The unit’s digit of (26387)2 will be 9.

(v) Since, 8 × 8 = 64

The unit’s digit of (52698)2 will be 4.

(vi) Since 0 × 0 = 0

The unit’s digit of (99880)2 will be O.

(vii) Since 6 × 6 = 36

The unit’s digit of (12796)2 will be 6.

(x) Since, 5 × 5 = 25

The unit’s digit of (55555)2 will be 5.

2. The following numbers are obviously not perfect squares. Give reason.

(i) 1057(ii) 23453(iii) 7928(iv) 222222 (v) 64000(vi) 89722(vii) 222000(viii) 505050

Sol: (i) 1057

Since, the ending digit is 7 (which is not one of 0, 1, 4, 5, 6 or 9)

∴1057 is not a perfect square.

(ii) 23453

Since, the ending digit is 7 (which is not one of 0, 1, 4, 5, 6 or 9).

∴23453 is not a perfect square.

(iii) 7928

Since, the ending digit is 8 (which is not one of 0, 1, 4, 5, 6 or 9).

∴7928 is not a perfect square.

(iv) 222222

Since, the ending digit is 2 (which is not one of 0, 1, 4, 5, 6 or 9).

∴222222 is not a perfect square.

(v) 64000

Since, the number of zeros is odd.

∴64000 is not a perfect square.

(vi) 89722

Since, the ending digits is 2 (which is not one of 0, 1, 4, 5, 6 or 9).

∴89722 is not a perfect square.

(viii) 222000

Since, the number of zeros is odd.

∴222000 is not a perfect square.

(viii) 505050

The unit’s digit is odd zero.

∴505050 can not be a perfect square.

3. The squares of which of the following would be odd numbers?

(i) 431(ii) 2826(iii) 7779(iv) 82004

Sol: Since the square of an odd natural number is odd and that of an even number is an even number.

(i) The square of 431 is an odd number.

[∵ 431 is an odd number.]

(ii) The square of 2826 is an even number.

[∵ 2826 is an even number.]

(iii) The square of 7779 is an odd number.

[∵ 7779 is an odd number.]

(v) The square of 82004 is an even number.

[∵ 82004 is an even number.]

4. Observe the following pattern and find the missing digits.

112 =

121

1012 =

10201

10012 =

1002001

1000012 =

1.............2 ............. 1

100000012 =

............

Sol: Observing the above pattern, we have

(i) (100001)2 - 10000200001

(ii) (10000001)2 = 100000020000001

5. Observe the ,following pattern and supply the missing number.

112 = 121

1012 = 10201

101012 = 102030201

10101012 =

..............2 = 10203040504030201

Sol: Observing the above, we have

(i) (1010101)2 = 1020304030201

(ii) 10203040504030201 = (101010101)2

6. Using the given pattern, find the missing numbers.

12 + 22 + 22 = 32

22 + 32 + 62 = 72

32 + 42 + 122 =132

42 + 52 + —2 = 212

52 + —2 + 302 = 312

62 + 72 + —2 = —2

Note: To find pattern:

Third number is related to first and second number. How?

Fourth number is related to third number. How?

Sol: The missing numbers are

(i) 42 + 52 + 202 = 212

(ii) 52 + 22 + 302 = 312

(iii) 62 + 72 + 422 = 432

7. Without adding, find the sum.

(i) 1 + 3 + 5 + 7 + 9

(ii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19

(iii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 +19

Sol: (i) The sum of first 5 odd = 52

= 25

(ii) The sum of first 10 odd numbers = 102

= 100

(iii) The sum of first 12 odd numbers = 122

= 144

8. (i) Lxpress 49 as the sum of 7 odd numbers.

(ii) Express 121 as the sum of 11 odd numbers.

Sol: (i) 49 = 72 = Sum of first 7 odd numbers

= 1 + 3 + 5 + 7 + 9 + 11 + 13

(ii) 121 = 112 = Sum of first 11 odd numbers

= 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21

9. How many numbers lie between squares of the following numbers?

(i) 12 and 13(ii) 25 and 26(iii) 99 and 100

Sol: Since between n2 and (n + 1)2, there are 2n non-square numbers.

∴ (i) Between 122 and 132, there are 2 × 12, i.e. 24 numbers

(ii) Between 252 and 262, there are 2 × 25, i.e. 50 numbers

, n2 – 1 = 92 – 1

Answered by shivanshagnihotri187
0

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