find the Trigonometric ratios of 270
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Step-by-step explanation:
sin( 270−Θ)=sin[180+(90−Θ 270 − Θ ) = s i n [ 180 + ( 90 − Θ )] ...
cos( 270−Θ)=cos[180+(90−Θ 270 − Θ ) = c o s [ 180 + ( 90 − Θ )] ...
tan( 270−Θ)=tan[180+(90−Θ 270 − Θ ) = t a n [ 180 + ( 90 − Θ )] ...
csc(270−Θ)=1sin(270+Θ) ...
sec(270−Θ)=1cos(270+Θ) ...
cot(270−Θ)=1sin(270−Θ)
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Answer:
3 cubed times by 10 is the calculation i got pls mark brainliest
Step-by-step explanation:
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