Find the trisectional points of line joining(2,6) and (-4,8)
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Answer:
A(2,6) B(_4,8)
AB line segment divided ratio into 1:2
section formula
p(xy)=(M1x2 +M2x1/M1+M2,M1y2+m2y1/m1+m2
m1:m2=1:2
1(_4)+2(2)/1+2,1(8)+2(6)/1+2
_4+4/3,8+12/3
(0,20/3)
Qdivides ratio 2:1
m1:m2=2:1
2(_4)+1(2)/2+1,2(8)+1(6)/2+1
_8+2/3,16+6/3
-6/3,22/3
(-2,22/3)
trisectional points are P(0 20/3)and Q(-2,2/3)
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