Question

Find the trisectional points of line joining (2, 6) and(-4, 8)

Answer 1

Step-by-step explanation:

Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then 

(x,y)=(m+nmx2+nx1,m+nmy2+ny1)

Let P and Q be the points of trisection of line joining the points A(4,1) & B(-2,-3).

Then, AP = PQ = QB

Now, P divides AB in the ratio 1:2 and Q divides AB in the ratio 2:1.

Therefore,

Coordinates of P = (3(−7+4),34−4)=(−1,0)

Coordinates of Q = (3(−14+2),38−2)=(−4,2)

Hence, the two points of trisection are P(−1,0) and (−4,2).