Question

Find the TSA and LSA of a cubical box whose diagonal is 20 me?

Answer 1

diagonal=20m

$\sqrt{3} a = 20$

$a = \frac{20}{ \sqrt{3} }$

now

TSA=

$6( {a}^{2} )$

=

$6( { \frac{20}{ \sqrt{3} } })^{2}$

=

$\frac{(6 \times 400)}{3}$

=

$800 {m}^{2}$

LSA

$4( {a}^{2} )$

=

$4( { \frac{20}{ \sqrt{3} } })^{2}$

=

$\frac{1600}{3}$

=

$533.33 \: {m}^{2}$