Question

Find the TSA of cuboid whose
Length = 5 m
Breadth = 1 m
Height = 2 m

Answer 1

Answer:

Given :

L = 5 m

B = 1 m

H = 2

Solution :-

TSA = 2(5 × 1 + 1 × 2 + 5 × 2)

TSA = 2(5 + 2 + 10)

TSA = 2(17)

TSA = 34 m

Answer 2

(1) length =12 cm breadth =10 cm height =5 cm

TSA=2(lb+bh+lh)=2[12×10+10×5+5×12]

TSA=2[120+50+60]=2×230

[TSA=460cm

2

]

(2) length =5 cm breadth =3.5 cm height =1.4 cm

TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5]

TSA=2[17.5+4.90+7.0]=2[29.4]

[TSA=58.8cm

2

]

(3) length =2.5 cm breadth =2 m height =2.4 m

TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025]

TSA=2[0.05+4.8+0.0600]=2[4.91]

(4) length =8 m breadth =5 m height =3.5 m

TSA=2(lb+bh+lh)=2[8×5+5×3.5+3.5×8]

TSA=2[40+17.5+28.0]=2[85.5]

[TSA=171.0m

2

]