Question

find the turning values of y=x^3-3x^2-9x+5​

Answer 1

Answer:

solved

Step-by-step explanation:

y = x³ - 3x² - 9x + 5​

y' = 3x² - 6x - 9 = 0  , x = -2 , 3

y'' = 6x - 6

y''(-2) = -18 → point of maxima

y''(3) = +12 → point of minima

ymax = y(-2) =  -8 - 12 +18 + 5​ = 3

ymin = y(3) = 3³ - 3³ - 27 + 5​ = -22

(-2,3) → point of maximum

(3,-22) → point of minimum