Question

Find the two consecutive even integers whose product is 120.

Answer 1

let x.... be the 1st even number

x+2... be the 2nd even number

x(x+2) = 120

x^2 + 2x - 120 = 0

(x-10)(x+12)= 0

x1=10/×2 =-12...1st even number

x1=12/×2 =-10...2nd even number

Answer 2

Answer:

the consecutive even int

is 10 and 12

10*12=120..

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