find the two consecutive even natural numbers such that the sum of their squares is 62
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Your question needs a correction :
Correct question : sum of their squares = 52
Solution
Let required numbers are 2x and 2( x + 1 ) ,
Given that the sum of their squares will be 52 ,
= > ( 2x )² + { 2( x + 1 ) }² = 52
= > 4x² + { 4( x² + 1 + 2x ) } = 52
= > 4x² + 4x² + 4 + 8x = 52
= > 8x² + 4 + 8x = 52
= > 8x² + 4 - 52 + 8x = 0
= > 8x² + 8x - 48 = 0
= > x² + x - 6 = 0
= > x² + ( 3 - 2 )x - 6 = 0
= > x² + 3x - 2x - 6 = 0
= > x( x + 3 ) - 2( x + 3 ) = 0
= > ( x + 3 ) ( x - 2 ) = 0
= > x = - 3 or x = 2
Given that numbers are natural numbers , so value of x is 2.
Hence,
Consecutive numbers are 2x = 2( 2 ) = 4 and 2( x + 1 ) = 2( 2 + 1 ) = 2( 3 ) = 6
joshimishi33:
Thx a lot dear i also thought of the mistake given in question as cause i was solving a paper in which this question was printed
Answered by
0
Answer:
the questions 52 not 62 & the answer is 4^2+6^2
Step-by-step explanation:
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