Question

Find the two consecutive integers, whose sum of their squares is 365.
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Answer 1

Answer:

two consecutive positive integers=13,14

Explaination:

Let the consecutive numbers be x,x+1

Sum of their squares x2+(x+1)2=365x2+x2+2x+1=3652x2+2x−364=0x2+x−182=0x2+14x−13x−182=0x(x+14)−13(x+14)=0(x+14)(x−13)=0x=−14,13

x=13 

two consecutive positive integers=13,14