Find the two consecutive multiples of 8 such that their sum is equal to 248.
Answers
Step-by-step explanation:
Let the first multiple of 8 be 8x.
Therefore the second consecutive multiple of 8 will be 8(x+1)
Also the third consecutive multiple of 8 will be 8(x+2).
It is given that the sum of these three consecutive multiples of 8 is 888
=> 8x + 8(x+1) + 8(x+2) = 888
=> 8x + 8x + 8 + 8x + 16 = 888
=> 24x + 24 = 888
Take 24 on the RHS
=> 24x = 888 - 24
=> x = 864/24
=> x = 36.
Therefore First multiple of 8 be 8x = 8 x 36 = 288
Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296
Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304
If we sum up these three multiples i.e (288 + 296 + 304) we get 888
Answer:
15 and 16 are the multiples of 8.
Step-by-step explanation:
Let take consecutive multiples be 8x, 8x+8.
So, 8x + 8x + 8 = 248
16x +8 = 248
6x = 248 - 8
16x = 240
x = 240/16
x = 15
So, x = 15
8x = 8(15)
= 120
8x + 8 = 8(15) +8 nothing but 8(16)
= 120 + 8
= 128
Verification :
8x + 8x + 8 = 248
we know the values of 8x, 8x + 8
120 + 128 = 248