Question

find the two consecutive odd integers whose sum of squares is 290​

Answer 1

Step-by-step explanation:

let the nos. be x and x+2

therefore x2 + ( x+2 )2 = 290

x2 + x2 + 4 +4x = 290

2x2 +4x +4 =290

x2 + 2x +2 = 145

x2 +2x -143= 0

x2 + 13x-11x -143 =0

x(x+13)-11(x-13) =0

(x-11) (x+13) =0

therefore x= 11 and 13

therefore the nos. are 11 and 13

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Answer 2

Answer:

I hope upper attachment will help you✌