Find the two consecutive odd
number whose product is 99
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Let consecutive no. Be (2x+1) and (2x+3).
Now according to question :-
(2x +1) (2x +3) = 99
2x ( 2x+3) +(2x+3) =99
4x^2 +6x +2x +3x =99
4x^2 + 8x +3 =99
x^2 +2x - 96 =0
x^2 +(6-4)x -24 =0
x^2 + 6x - 4x - 24 =0
x (x+6) -4 (x+6) =0
(x+6) (x-4) =0
When (x+6) =0
x=-6 ans.
when (x-4) =0
x = 4 ans.
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