Question

find the two consecutive odd positive integers if the sum of their squares is 290 . ( by using quadratic formula).​

Answer 1

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST

Answer 2

Hey friend here is the solution for this question.....

Assume first odd positive integer is = a

then by default next consecutive odd positive integer will be a+2

so....

${a}^{2} + {(a + 2)}^{2} = 290 \\ 2 {a}^{2} + 4a - 286 = 0$

a=11

so a+2=13

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