Question

find the two consecutive positive integers, whose sum of their squares is 365​

Answer 1

Answer:

Let the no. be  x and x+1

 then we have x²+(x+1)²=365

                    2x²+2x-364=0

                    x²+x-182=0

                    x²+14x-13x-182=0

                    (x+14)(x-13)=0

                That gives x=13 Avoiding negative value

                one number is 13 and other one 14.

Answer 2

Answer:

$13 \: and \: 14$

Step-by-step explanation:

It is the correct answer.

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