Question

Find the two consecutive positive
irtegers, whose sum of their squares is 365 ​

Answer 1

Answer:

13 and 14

Step-by-step explanation:

13× 13 = 169

14×14 = 196

169 + 196= 365

Answer 2

Answer:

13,14

Step-by-step explanation:

let the two n.of be x and x+1 because they are consecutive which means like 2 3,. 4 5., 16 17, ok

given x^2+(x+1)^2=365

now use( a+b)^2 identity

x^2+x^2+1+2x=365

2x^2+2x-324=

divide both sides with 2

x^2+x-162=0

now use quad radio equation or factorisation to find x

x=13 ×+1=14