Question

Find the two consecutive positive numbers whose sum of square is 290.​

Answer 1

Answer:

Let x an odd positive integer

Then, according to question

x

2

+(x+2)

2

=290

2x

2

+4x−286=0

x

2

+2x−143=0

x

2

+13x−11x−143=0

(x+13)(x−11)=0

x=11 as x is positive

Hence required integers are 11 and 13

Answer 2

Answer:

ANSWER

Let x an odd positive integer

Then, according to question

x

2

+(x+2)

2

=290

2x

2

+4x−286=0

x

2

+2x−143=0

x

2

+13x−11x−143=0

(x+13)(x−11)=0

x=11 as x is positive

Hence required integers are 11 and 13