Question

find the two consecutive positive odd integers whose sum is 76 ​

Answer 1

Answer:

Step-by-step explanation:

Let the two consecutive odd integers are 2x+1 and 2x+3

According to the question,

⇒  2x+1+2x+3=76

⇒  4x+4=76

⇒  4x=72

⇒  x=

4

74

​

=18

So, one integer=2x+1=37

another one=2x+3=39

∴  The required two consecutive positive odd integers are 37 and 39.

Let the two consecutive odd integers are 2x+1 and 2x+3

According to the question,

⇒  2x+1+2x+3=76

⇒  4x+4=76

⇒  4x=72

⇒  x=

4

74

​

=18

So, one integer=2x+1=37

another one=2x+3=39

h

h

Answer 2

Answer:

$\huge \: answer$

Let the two consecutive odd integers are 2x+1 and 2x+3

According to your question:-

$\longrightarrow \: 2x + 1 + 2x + 3 = 76 \\ \longrightarrow \: 4x + 4 = 76 \\ \longrightarrow \: 4x = 72 \\ \longrightarrow \: x = \frac{74}{4} = 18$

So,one integer => 2x+1=37

Another one=>2x+3=39

=>> Hence,the required two consecutive positive odd integers are 37 and 39.

Hope it helps!

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