Question

Find the two-digit number thought by me
The digit at the tens place is 5 less than twice
the digit at units place.
The sum of the original number and the number
obtained by interchanging the digits is 176.​

Answer 1

Answer:

Step-by-step explanation:

10x+y

X=2y-5

10x+y+10y+x=176

11x+11y =176

X+y=16

2y-5+y=16

3y=21

Y=7

X=9

97 is the right nd final answer...

Answer 2

Answer:

Number is 62

let say the digit on one's place so 3x is digit on ten's place

1. so the no. is 10×3×+×=31×

Now if we reverse the position of digit new number is

10×+3×=13×

as given new no. is less by 36 from old no.

31×36=13×

18×=36

x=2

so the no. is 10×3×2+2=62

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