Question

find the two-digit numbers a and b such that the number 65ab0 is divisible by 66.

1) 15, 16
2) 16, 16
3) 17, 17
4) 17, 18

Answer 1

The answer will be option c 17 and 17 because if we will put 17 and 17 in place of a and b then the number will be 6517170 which is divisible by 66 as 6517170÷66 =98745

Answer 2

Answer:

3) 17,17

Step-by-step explanation:

For the number to be divisible by 66, It must be divisible by 2 , 3, 11.

Option 1) 15,16

Number- 6515160

Divisible by 2 - Last digit 0,2,4,6,8. Yes, divisible.

Divisible by 3 -Sum to be divisible by 3. Yes, divisible.

Divisible by 11 -Diff of alternate sum from left  to right divisible by 11 - Non divisible.

Option 2) 16,16

Number- 6516160

Divisible by 2 - Last digit 0,2,4,6,8. Yes, divisible.

Divisible by 3 -Sum to be divisible by 3. Non divisible.

Option 3) 17,17

Number- 6517170

Divisible by 2 - Last digit 0,2,4,6,8. Yes, divisible.

Divisible by 3 -Sum to be divisible by 3. Yes, divisible.

Divisible by 11 -Diff of alternate sum from left  to right divisible by 11 - Yes, divisible.

Option 4) 17,18

Number- 6517180

Divisible by 2 - Last digit 0,2,4,6,8. Yes, divisible.

Divisible by 3 -Sum to be divisible by 3. Non divisible.