Math, asked by nagartanishka584, 19 days ago

find the two integers which have diffrence 6 and sum -18​

Answers

Answered by sheeb12ansari
0

Given: The difference between two numbers is6 and the sum is-18.

We have to find the numbers.

We are solving in the following way:

Let assume the number will be xandy.

We have,

=>x-y=6\\=>x+y=-18

Now, by shifting 'y' on the right-hand side:

=>x-y=6\\=>x=6+y

By putting the value of 'x' in the equationx+y=-18:

=>x+y=-18\\=>6+y+y=-18\\=>6+2y=-18\\=>2y=-18-6\\=>2y=-24\\\\=>y=\frac{-24}{2} \\\\=>y=-12

Now by putting the value of 'y' in the equationx+y=-18:

=>x+y=-18\\=>x+(-12)=-18\\=>x=-18+12\\=>x=-6

Hence, the two integers will be-12 and -6.

Answered by niteshrajputs995
0
  • As per the data given in the question, we have to find the value of the expression.

         Given data:- The difference between two numbers is 6,

                                and the sum is 18.

          To find:- Value of the expression.

          Solution:-

         Let assume the number will be x and y.

            We have,

           \begin{array}{l}=>x-y=6 \\=>x+y=-18\end{array}

      Now, by shifting y on the right-hand side:

          \begin{array}{l}=>x-y=6 \\=>x=6+y\end{array}

     By putting the value of x in the equation x+y=-18.

            \begin{array}{l}=>x+y=-18 \\=>6+y+y=-18 \\=>6+2 y=-18 \\=>2 y=-18-6 \\=>2 y=-24 \\=>y=\frac{-24}{2} \\=>y=-12\end{array}

    Now put the value of y in the equation x=y=-18.

           \begin{array}{l}=>x+y=-18 \\=>x+(-12)=-18 \\=>x=-18+12 \\=>x=-6\end{array}

  Hence we  will get the value y=-12,x=-6.

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