Question

Find the two natural numbers which differ by 3 and whose squares have the sum 117

Answer 1

Answer:

let firstl no be x

second no be x+3

Step-by-step explanation:

x^2+(x+3)^2=117

x^2+x^2+9+6x=117

2x^2+6x=108

2(x^2+3x)=108

x^2+3x=54

x^2+3x-54=0

x(x+9)-6(x+9)=0

(x-6) (x+9)=0

x-6=0

x=6

so first no is 6

second no is x+3