Find the two natural numbers which differ by 5 and the sum of whose squares is 97.
Problems based on Quadratic equations
Do in Ur book and attach the pic.
Answers
Answered by
3
Those numbers are 9 and 4
9-4=5
(9)²+(4)²=81+16=97
9-4=5
(9)²+(4)²=81+16=97
shaiksalman580:
plzz mark it as brainliest answer
Ok
method
Answered by
8
plz mark it as brainiest as I bhave solved it
Attachments:
Similar questions