find the two number such that the sum of twice the first and thrice the second is 92,and four times the first exceed the second by2.
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2x + 3y = 92 (1)
4x = y + 2
4x - y = 2 (2)
multiply equation (2) with 3
12x - 3y = 6
2x + 3y = 92
12x - 3y = 6
14x = 98
x = 98/14
x = 7
2x + 3y = 92
2(7) + 3y = 92
3y = 92 - 14
3y = 78
y = 78/3
y = 26
therefore x = 7, y= 26
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