Question

find the two number whose sum is 20, and the sum of whose square is 208​

Answer 1

Answer:

20 -10*2 --20 where as 2

Step-by-step explanation:

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Answer 2

Answer:

$two \: number \: is \: x \: and \: y \\ \: {x > y} \\ x + y = 20 - - - - - - {i} \\ x { }^{2} + y {}^{2} = 208 - - - - -{ii} \\ from \: eq \: i \\ x = 20 - y \\ putting \: the \: value \: of \\: x \: in \: eq \: ii \: we \: get \\(20 - y) ^{2} + y ^{2} = 208 \\ 400 + y {}^{2} - 40y + y {}^{2} = 208 \\ 2y {}^{2} - 40y = 208 - 400 \\ 2y ^{2} - 40y = - 192 \\ y ^{2} - 20y = - 96$

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Step-by-step explanation:

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