Question

Find the two numbers having the LCM of 120 and HCF of 6

Answer 1

Answer:

Let the numbers be x and y.

LCM ( x, y ) = 120 ( Given )

HCF ( x, y ) = 6 ( Given )

One number, x = 30 ( Given )

Now,

( x ) × ( y ) = LCM × HCF

y = ( LCM × HCF ) / x

y = ( 120 × 6 ) / 30

y =24

Answer 2

Answer:

the two numbers are 24 and 30