find the two numbers nearest to 5000 which is exactly divisible by 5, 7, 14 and 21
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Answer:
The LCM of 7,6,5,4,3,2 is 420 (= 7*5*3*2*2). So, a number exactly divisible by 7,6,5,4,3,2 must be exactly divisible by 420. Now, we need a number near 10000 ..
Step-by-step explanation:
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Step-by-step explanation:
The LCM of 5, 7, 14 and 21 is 105
Now divide 5000 with 105
105 x 48 = 5040 ( 5040 = 5000 + 40 )
It means 40 is the number which when added to 5000 is exactly divisible by 5, 7, 14 and 21
Also 105 x 47 = 4935 ( 4935 = 5000 - 65 )
It means 65 is another number which when subtracted from 5000 is exactly divisible by 5, 7, 14 and 21
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