Find the two numbers such that he difference of their square is 189 and the sum of the numbers is 1521. plls it's urgent
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Let the two numbers be x&y
So, difference of their squares is 189.
So, x^2-y^2=189__________(1)
Sum of the numbers is 1521.
So,x+y=1521
=>y=1521-x______________(2)
Substituting, y=1521-x in eq(1)we get,
x^2-(1521-x)^2=189
=>x^2-(2313441+x^2-3042x)=189
=>x^2-2313441-x^2+3042x=189
=>3042x=189+2313441
=>3042x=2313630
=>x=2313630/3042
=>x=760.56
=761
Therefore the two numbers are 761 & 1521-761=760
So, difference of their squares is 189.
So, x^2-y^2=189__________(1)
Sum of the numbers is 1521.
So,x+y=1521
=>y=1521-x______________(2)
Substituting, y=1521-x in eq(1)we get,
x^2-(1521-x)^2=189
=>x^2-(2313441+x^2-3042x)=189
=>x^2-2313441-x^2+3042x=189
=>3042x=189+2313441
=>3042x=2313630
=>x=2313630/3042
=>x=760.56
=761
Therefore the two numbers are 761 & 1521-761=760
nibha15jan1981:
Thanks
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