Question

Find the two numbers such that if one is subtracted from the greater number, it is 3
times the smaller number and if 3 is subtracted from the smaller number, then it is
one-fifth of the greater number.​

Answer 1

Answer:

${\pink{\green{\sf{Greatest\:number(y)=25}}}}$

${\pink{\green{\sf{Smallest\:number(x)=8}}}}$

Step-by-step explanation:

$\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}$

• In the given question information given about two unknown numbers.

• According to given question :

$\underline \bold{given : } \\ \bold{\implies let \: greatest \: number = y} \\ \bold{\implies \: smallest \: number = x} \\ \\ \underline \bold {to \: find :} \\ \bold{ \implies x = ?} \\ \bold{ \implies y= ?}$

• Form 2 eqn from given information in the given where two eqn two unknown.

$\implies y - 1 = 3x \\ \implies y - 3x = 1 - - - - - (1) \\ \\ \implies x - 3 = \frac{y}{5} \\ \implies 5x - 15 = y \\ \implies 5x - y = 15 - - - - - (2)$

• Adding eqn (1) and eqn (2)

$\implies y - 3x + 5x - y = 1 + 15 \\ \implies2x = 16 \\ \implies x = \frac{16}{2} \\ \bold {\therefore x = 8} \\ \\ putting \: value \: of \: x \: in \: (1) \\ \implies y - 3x = 1 \\ \implies y - 3 \times 8 = 1 \\ \implies y = 1 + 24 \\ \bold{\therefore y = 25}$

Answer 2

Step-by-step explanation:

let the greater no be Y and smaller no be X

eqn 1 . Y-1=3X

Y-3X=1. eqn 1

X-3=Y÷5

5X-15=Y

5X-Y=15.. eqn 2

solve both eqn and get the values of X and Y....