Question

Find the two numbers such that one of the number exceeds the other by 21 and their sum
is 91?

Answer 1

Solution:

Let the first number be x.

Now, other number exceeds the first number by 21.

So,

→ Other number = x + 21

Also, it's given that,

→ Sum of two numbers = 91

So, according to the given condition,

→ x + x + 21 = 91

→ 2x + 21 = 91

→ 2x = 91 - 21

→ 2x = 70

→ x = 70/2

→ x = 35

So, the first number is 35

Therefore, second number will be,

= x + 21

= 35 + 21

= 56

★ So, the numbers are 35 and 56.

Answer:

• The numbers are 35 and 56.

Verification:

Sum of the numbers,

= 35 + 56

= 91

Difference between the numbers,

= 56 - 35

= 21

So, our answer is correct (Verified)

•••♪

Answer 2

Question :

Find the two numbers such that one of the number exceeds the other by 21 and their sum

is 91?

Answer :

$\sf\pink {Given :}$

• One number exceeds other by 21 .

• sum of that two numbers is 91 .

$\sf\pink {To\:find :}$

• The two numbers ?

Explanation :

• let one number be "x" .

• Therefore the other is x + 21 .

• their sum is 91 that is .

$\\ \longrightarrow\sf { x + x + 21 = 91}$

$\\ \longrightarrow\sf { 2x + 21 = 91}$

$\\ \longrightarrow\sf { 2x = 91 -21}$

$\\ \longrightarrow\sf { 2x = 70}$

$\\ \longrightarrow\sf { x = \dfrac {70}{2}}$

$\\ \longrightarrow\sf { x = 35}$

• One number is x

$\\ \longrightarrow\sf { x = 35}$

Therefore one number is 35 .

• other number is x + 21

$\\ \longrightarrow\sf { 35 + 21}$

$\\ \longrightarrow\sf { 56}$

Therefore the other number is 56 .

Verification :

one number + other number = 91

$\\ \longrightarrow\sf { 35 + 56 = 91}$

$\\ \longrightarrow\sf { 91 = 91}$

$\\ \longrightarrow\sf { LHS = RHS}$

hence verified