Question

Find the two numbers which differ by 4 and such that one half of the greater exceeds one sixth of the lesser by 8

Answer 1

Answer:

22 ; 18.

Step-by-step explanation:

let the smaller number be 'x'.

given that, the one half of the greater exceeds

one sixth of the smaller by 8.

1/6 * x +8 = greater number/2

X/6 +8 = greater number/2

48+x/6 = greater number/2

greater number = (48+x)/3

and also given that, difference of the two

numbers = 4

(48+x)/3 - x = 4

(48+x - 3x)/3 = 4

48 - 2x = 4*3

48 - 2x = 12

48 - 12 = 2x

36 = 2x

x = 36/2

x = 18.

Therefore, smallest number = 18 ,

largest number = (48+18)/3

= (66/3)

= 22.

Verification:

Difference = 4

22 - 18 = 4

4 = 4

Therefore, LHS = RHS.