Question

Find the two numbers whose sum and difference are 42 and 6 respectively​

Answer 1

Answer:

Let the two no.s be a and b

Then ATQ, we have

a+b=42.........(1)

a-b=6. ..........(2)

Adding 1 and 2 , we get

a+b+a-b=42+6

2a=48

a=48/2

a=24

Putting the value of a in eq.1 , we get

24+b=42

b=18

Step-by-step explanation:

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