find the two numbers whose sum is 50 and whose product is 400
Answers
Answer:
10 and 40
Step-by-step explanation:
x + y =50
xy = 400
Use substitution. X=50 - y
y (50 - y) = 400
50y - y^2 = 400
0 = y^2 -50y + 400
0 = (y -40)(y - 10)
y-40 = 0
y = 40
y - 10 = 0
y = 10
50-40 = 10
50-10 = 40
Answer:
Step-by-step explanation:
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Let x be the 1st no.
and y be the 2) no.
x + y =50
xy = 400
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Solving :
Use substitution. X=50 - y
y (50 - y) = 400
50y - y^2 = 400
0 = y^2 -50y + 400
0 = (y -40)(y - 10)
y-40 = 0
y = 40
y - 10 = 0
y = 10
50-40 = 10
50-10 = 40
We just got the same set of numbers twice, 10 and 40.
Therefore the first no= 10
second no. =40
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Verification 1)
We have to verify that 10+40 = 50
Therefore it is 50
Hence verified
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Verification 2)
We have to verify that 10×40= 400
Therefore it is 400
Hence verified
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Therefore the answer for your question
is =
first no= 10
second no. =40
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