Math, asked by pattnaiktridiboz40v9, 1 year ago

Find the two parallel sides of a trapezium whose area is 1.6dm²,altitude is 10dm and one of the parallel sides is longer than the other by 8dm.

Answers

Answered by nikiwowie
4

Answer:

4.16 dm

Step-by-step explanation:

Let one side be = x dm

so the other side = x - 8 dm

Area of Trapezium = 1/2(sum of parallel sides)*distance between them

Area = 1/2( x + x - 8) * 10

1.6 = 1/2(2x - 8) * 10

1.6/10 = x - 4

4.16 = x

x - 8 = 4.16 - 8

other side = -3.74 dm

Ans) the two parallel sides are 4.16 dm and -3.74 dm. (Check the question again from your book as sides cannot have a negative value.

Answered by Anonymous
2

Answer:

Refer the attachment.

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