Find the two parallel sides of a trapezium whose area is 1.6dm²,altitude is 10dm and one of the parallel sides is longer than the other by 8dm.
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Answer:
4.16 dm
Step-by-step explanation:
Let one side be = x dm
so the other side = x - 8 dm
Area of Trapezium = 1/2(sum of parallel sides)*distance between them
Area = 1/2( x + x - 8) * 10
1.6 = 1/2(2x - 8) * 10
1.6/10 = x - 4
4.16 = x
x - 8 = 4.16 - 8
other side = -3.74 dm
Ans) the two parallel sides are 4.16 dm and -3.74 dm. (Check the question again from your book as sides cannot have a negative value.
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