Find the two parallel sides of a trapezium whose area is 1.6m² , altitude is 10dm and one of the parallel sides is longer than the other by 8 dm.
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Let one of the parallel side be x
And other side=(x+0.8)m
Area of trapezium =1/2(sum of parallel side)×h
=1.6=1/2(x+x+0.8)×1
=1.6×2=2x +0.8
=3.2=2x+0.8
=3.2-0.8=2x
=2.4=2x
=x=1.2
So,the parallel sides are 1.2m and 1.2+0.8=2m
And other side=(x+0.8)m
Area of trapezium =1/2(sum of parallel side)×h
=1.6=1/2(x+x+0.8)×1
=1.6×2=2x +0.8
=3.2=2x+0.8
=3.2-0.8=2x
=2.4=2x
=x=1.2
So,the parallel sides are 1.2m and 1.2+0.8=2m
Anonymous:
Great , Thank you so much!!
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hope it will help you ......
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