Question

Find the two parallel sides of a trapezium whose area is 1.6 m², altitude is 10 dm and
one of the parallel sides is longer than the other by 8 dm.

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Answer 1

Answer:

Step-by-step explanation:

Given :-

Area of trapezium = 1.6 sq m

Altitude, h = 10 dm = 1 m

To Find :-

The two parallel sides.

Formula to be used :-

Area of trapezium

Solution :-

Let one of the parallel sides be x

And the other side be (x + 0.8) m

According to the Question

Area of trapezium, A = (1/2) × h × (a + b)

⇒ 1.6 = (1/2) × 1 × (x + x + 0.8)

⇒ 3.2 = 2x + 0.8

⇒ 2x = 3.2 - 0.8 = 2.4

⇒ x = 1.2 m

1st Side = 1.2 m

2nd Side = (x + 0.8) = 2 m

Hence, the parallel sides are 1.2 m and 2 m.

Answer 2

• Let one parallel side of trapezium be (M) m.

» One of the parallel sides is longer than the other by 8 m.

• Another side of trapezium be (M + 0.8) m.

• Area of trapezium = 1.6 m²

__________ [ GIVEN ]

• We have to find the two parallel sides of the trapezium.

____________________________

We know that..

» Area of trapezium = 1/2 × h × (d1 + d2)

Here..

d1 = M

d2 = M + 0.8

Put the known values in above formula

→ 1.6 = 1/2 × 1 × (M + M + 0.8)

→ 1.6 = 1/2 (2M + 0.8)

→ 1.6 = 1/2 × 2(M + 0.4)

→ 1.6 = M + 0.4

→ 1.6 - 0.4 = M

→ 1.2 = M

→ M = 1.2

____________________________

• One parallel side of trapezium = M

→ 1.2 m

• Another parallel side of trapezium = M + 0.8

→ 1.2 + 0.8

→ 2 m

___________________________

1.2 m and 2 m is the are the two parallel sides of the trapezium.

_______ [ ANSWER ]

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