Find the two parallel sides of a trapezium whose area is 1.6 sq. m , altitude is 10 dm and one of the parallel sides is longer than the other by 8 dm.
plz give me answer soon
Answers
Answered by
151
heya frnd
hope this helps u
Given area of trapezium = 1.6 sq m
Altitude, h = 10 dm = 1 m
Let one of the parallel sides be x then the other side will be (x + 0.8) m
Recall that area of trapezium, A = (1/2) x h x (a + b)
1.6 = (1/2) × 1 × (x + x + 0.8)
3.2 = 2x + 0.8
2x = 3.2 - 0.8 = 2.4
Therefore, x = 1.2 m
(x + 0.8) = 2 m
Thus the parallel sides are 1.2m and 2 m or 12 d and 20 d
hope this helps u
Given area of trapezium = 1.6 sq m
Altitude, h = 10 dm = 1 m
Let one of the parallel sides be x then the other side will be (x + 0.8) m
Recall that area of trapezium, A = (1/2) x h x (a + b)
1.6 = (1/2) × 1 × (x + x + 0.8)
3.2 = 2x + 0.8
2x = 3.2 - 0.8 = 2.4
Therefore, x = 1.2 m
(x + 0.8) = 2 m
Thus the parallel sides are 1.2m and 2 m or 12 d and 20 d
Anonymous:
Thanks a lot
can l call u di
of course
u can inbox me
if u have any doubts
yaa
sure
if u like my answer folliw me
thq tanisha
Answered by
3
Answer:
answer is given below
Step-by-step explanation:
hope it helps you
thanku
Attachments:
Similar questions