Question

find the two parallel sides of a trapezium whose area is 1.6 m² , altitude is 10 dm and one of the parallel sides is longer than the other by 8 dm. ​

Answer 1

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${\tt {\pink {\underline{\underline {\huge {Given}}}}}}$

Area = 1.6m^2

= 160dm

Height = 10dm

${\tt {\pink {\underline{\underline {\huge {Solution}}}}}}$

Let one side x then,

Other side = x+8

$\star \: \tt\red{According\: to \: Question} \: \star$

Area = 1/2×Sum of parallel sides×height

➨ 160dm = 1/2 × ( x+ x+ 8) × 10

➨ 160/10 = 1/2 × ( 2x + 8)

➨ 16 × 2 = 2x + 8

➨32 - 8 = 2x

➨ 24/2 = x

➨12 = x

Other side = x + 8

= 12 + 8

= 20

Therefore, parallel sides of trapezium are 12dm and 20dm.

$<marquee>$hope it helps you....✌✌

Answer 2

One side = 12dm and other side = 20dm

Given that :-

• Area of trapezium = 160dm
• Altitude of trapezium = 10dm.

To Find :-

• Calculate the length of one side and other side of trapezium.

Solution :-

Let,

• The one side of trapezium is "r"
• And the other side of trapezium is "r + 8".

As we know that,

• Area of trapezium = 1/2 × Sum of || sides × height .

=> 160 = 1/2 × ( r + r + 8 ) × 10

=> 160/10 = 1/2 × 2r + 8

=> 16 × 2 = 2r + 8

=> 32 = 2r + 8

=> 2r = 32 - 8

=> 2r = 24

=> r = 12 .

Hence,

• One side of trapezium = r = 12dm.

• Other side of trapezium = r + 8 = 20dm.