Find the two parallel sides of a trapezium whose area is 1.6 meter square, altitude is 10 dm
and one of the parallel sides is longer than the other by 8 dm.
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Answer:hey mate here is your answer
Step-by-step explanation:
Given :-
Area of trapezium = 1.6 sq m
Altitude, h = 10 dm = 1 m
To Find :-
The two parallel sides.
Formula to be used :-
Area of trapezium
Solution :-
Let one of the parallel sides be x
And the other side be (x + 0.8) m
According to the Question
Area of trapezium, A = (1/2) × h × (a + b)
⇒ 1.6 = (1/2) × 1 × (x + x + 0.8)
⇒ 3.2 = 2x + 0.8
⇒ 2x = 3.2 - 0.8 = 2.4
⇒ x = 1.2 m
1st Side = 1.2 m
2nd Side = (x + 0.8) = 2 m
Hence, the parallel sides are 1.2 m and 2 m.
hope it helps
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