Question

Find the two parallel sides of a trapezium whose area is 1.6 m², altitude is 10 dm
and one of the parallel sides is longer than the other by 8 dm.
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Answer 1

Answer:

Given : two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.

To find : the two numbers

Let x and y be the two numbers required.

According to the question :

⇒2x+3y=92 ........(1)

⇒4x−7y=2 ........(2)

multiply the first equation by 2 , and subtract eqn (1) from eqn (2)

4x+6y=184

−(4x−7y=2) , we get

⇒13y=182

⇒y=13182=14

Put y=14 in (1)

2x+3y=92

⇒2x+3×14=92

⇒2x=92−42=50

∴x=250=25

∴x=25 and y=14