Question

Find the two parallel sides of a trapezium whose area is 1.6 m², altitude is 10 dm
and one of the parallel sides is longer than the other by 8 dm.​

Answer 1

Step-by-step explanation:

Area of trapezium = 1/2(a+b)h

= 1/2(a+b)h= A

=1/2(x+x+8)10= 1.6

=1/2(2x+8) 10= 1.6

= 1/2*2(x+4)10=1.6

=2/2(x+4)10=1.6

=(x+4)10= 1.6

=10x+40=1.6

=10x+40=1.6*100

=10x+ 40=160

=10x=160-40

=10x=120

x=120/10

x=12

one is 12dm

and another one is 12+8=20