Question

Find the two parallel sides of a trapezium whose area is 1.6 m2, altitude is 10 dm
and one of the parallel sides is longer than the other by 8 dm.​

Answer 1

Answer:

area of trapezium= 1.6 sq m

altitude h = 10 dm = 1 m

let one of the parallel sides be x then the other side will be ( x + 0.8 ) m

Recall that area of trapezium , A = ( 1/2)

x h x ( a + b )

1.6 = ( 1/ 2) ×1 × ( x + x + 0.8 )

3.2 = 2 x + 0.8

2x = 3.2- 0.8 = 2.4

therefore , x = 1.2 m

( x+0.8 ) = 2m

thus the parallel sides are 1.2 m and 2m

Step-by-step explanation:

please support me and mark me as brainliest