Find the two parallel sides of a trapezium whose area is 1.6 sq.m, altitude is 10 dm and one of the parallel sides is longer than the other by 8 dm.
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Let the lengths of the parallel sides of the trapezium be 3a dm and 4a dm
Area of a trapezium =21×(Sumofparallelsides)×height
=>21×(3a+4a)×9dm=126dm2
=>21×7a×9=126
=>a=4
Hence, the lengths of the parallel sides of the trapezium are 3a=12dm and 4a=16dm
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